Using SET and time in batch file, want to get the difference in time

Check out this ultimate script that queries system time through WMI.
Link Removed...[/i]

Beware of the confusion Octal/Decimal if the variable is 08 or 09

So modification needed...

set T1=%TIME%
echo Start time= %T1%
set HH=%T1:~0,2%
set MM=%T1:~3,2%
set SS=%T1:~6,2%
Rem To remove confusion Octal/Decinal with 08 and 09
IF %T1:~0,1%==0 set HH=%T1:~1,1%
IF %T1:~3,1%==0 set MM=%T1:~4,1%
IF %T1:~6,1%==0 set SS=%T1:~7,1%

Envoy

Beware of the confusion Octal/Decimal if the variable is 08 or 09

Love it when people dig up old threads.
Your statement is clearly defined in the help for the SET command.

Numeric values are decimal numbers, unless
prefixed by 0x for hexadecimal numbers, and 0 for octal numbers.
So 0x12 is the same as 18 is the same as 022. Please note that the octal
notation can be confusing: 08 and 09 are not valid numbers because 8 and
9 are not valid octal digits.