command line arguments in dos

Hi All,

I am new to dos.
I have to use some command which should accept source and destination path as command line arguments and the file name to copy.
whenever i supply three arguments my functionality should work.
how can i achieve this?

Thanks in advance.

can anybody please help me...

What do you need help with ?
Do you have to create a program to accept and process the parameters, or does this program already exist and you need to know how to supply parameters on the command line ?

thank you...
i need a program for this.

When you say program, you mean batch script ?

Actually speaking i do not know how to achieve this...(through batch file or command etc)
Please give me possible ways.
I am sorry as i am new to this forum as well as dos.

So your requirement is
receive 3 parameters
Source Directory (%1)
Destination Directory (%2)
Filename (%3)

Copy filename from Source to Destination

The simplest way is (with no error checking)

Code: [Select]

Copy %1\%3 %2

Thank you gpl.
Its working.
I have created a batch file with your command.
I have passed three arguments to the file while running it.

Can we copy the file from one machine to other machine?