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Microsoft => Microsoft DOS => Topic started by: _unknown_ on February 07, 2016, 11:48:48 AM

Title: Copy the filename of a file and replace the strings inside the same file-batch
Post by: _unknown_ on February 07, 2016, 11:48:48 AM

I have a folder with numerous files wherein I want to copy the file name of the file and want to replace strings inside that same file with the file name copied but the last 4 character should be changed. *This isn't the same with the previous post.

I have this files with this file name:

Code: [Select]

Data2016001045000.level1_level2.newDATA_main.vrt
Data2016002055000.level1_level2.newDATA_main.vrt
Data2016003055000.level1_level2.newDATA_main.vrt
and so on . . .
Each file looks like this:

Code: [Select]

   <Insert="Line 1">
     <Insert="Line 2">[b]file1.vrt[/b]</Line2>
     <Insert="Line 2">1</Line2>
     <Insert="Line 3">file2.vrt</Line3>
     <Insert="Line 3">1</Line3>
     <Another line="Line 4">0</Line4>
   </Insert>

Let's say the first file name to copy is Data2016001045000.level1_level2.newDATA _main.vrt. Copied file name will replace the file1.vrt and file2.vrt but having the last 4 character(main) changed to data1 and data2. So the file should look like this:

Code: [Select]

   <Insert="Line 1">
     <Insert="Line 2">[b]Data2016001045000.level1_level2.newDATA_data1.vrt[/b]</Line2>
     <Insert="Line 2">1</Line2>
     <Insert="Line 3">[b]Data2016001045000.level1_level2.newDATA_data2.vrt[/b]</Line3>
     <Insert="Line 3">1</Line3>
     <Another line="Line 4">0</Line4>
   </Insert>
Here is what I have so far. Need help:

Code: [Select]

@echo off

set "search1=file1.vrt"
set "search2=file2.vrt"
set "src=C:\path\to\source\files"
pushd "%src%"

for /f "delims=" %%a in ('dir /b /a-d "*.newDATA_main.vrt" ') do (
   echo Processing "%%a"
   set "filename=%%a"
   (
      for /f "usebackq delims=" %%b in ('type "%filename%" ^& break ^> "%filename%" ') do (
         set "line=%%b"
         set "line=!line:%search%=%filename%data1.vrt!"
         set "line=!line:%search%=%filename%data2.vrt!"
      )   
   ))>"%dst%\%%a.tmp" echo(!line1! !line2!


Title: Re: Copy the filename of a file and replace the strings inside the same file-batch
Post by: foxidrive on February 07, 2016, 11:29:05 PM

The details you show are terrible.  Nothing learned from my previous rant? :D
There was a good deal of comment via PM...

This gives you a way to separate the filename elements using the data that you provided.

Code: [Select]

@echo off
set "src=C:\path\to\source\files"
pushd "%src%"
   for /f "tokens=1,2 delims=_" %%a in ('dir /b /a-d "*.newDATA_main.vrt" ') do (
     echo "%%a_%%b_data1.vrt"
     echo "%%a_%%b_data2.vrt"
   )
pause


Title: Re: Copy the filename of a file and replace the strings inside the same file-batch
Post by: foxidrive on February 08, 2016, 02:38:20 AM

Quote from: _unknown_ on February 07, 2016, 11:48:48 AM

What do you mean terrible? :( I've provided a post with complete detail

Complete detail is when the line says "My name is Peter"
and you provide information that says something like  "My name is xxxxx"
instead of "abc 1111 data"

The reason why that is so important, is that Batch file code often changes when the data/text changes.

The code I provided above just shows how you can separate the filename tokens - it was quick to post.

Title: Re: Copy the filename of a file and replace the strings inside the same file-batch
Post by: Squashman on February 08, 2016, 10:47:35 AM

Is this like the 4th thread started on this same topic?

Title: Re: Copy the filename of a file and replace the strings inside the same file-batch
Post by: _unknown_ on February 08, 2016, 03:57:34 PM

Quote from: Squashman on February 08, 2016, 10:47:35 AM

Is this like the 4th thread started on this same topic?

Sorry but it's not the same with the previous topic. Previous topic was to insert a file inside another file. This is copying the filename and then inside that same file you'll have to search and replace a string using the filename you copied and just change the last part.

Title: Re: Copy the filename of a file and replace the strings inside the same file-batch
Post by: _unknown_ on February 09, 2016, 09:07:40 PM

Quote from: _unknown_ on February 08, 2016, 07:21:25 AM

I can do the "replace" thing for every newDATA_main.vrt using this code:

This is for data1.bat

Code: [Select]

@echo off
    setlocal enableextensions disabledelayedexpansion

    set "search=file1.vrt"
    set "replace=D2016001045000.level1_level2.newDATA_data1.vrt"

    set "textFile=D2016001045000.level1_level2.newDATA_main.vrt"

    for /f "delims=" %%i in ('type "%textFile%" ^& break ^> "%textFile%" ') do (
        set "line=%%i"
        setlocal enabledelayedexpansion
        set "line=!line:%search%=%replace%!"
        >>"%textFile%" echo(!line!
        endlocal
    )

This is for data2.bat

Code: [Select]

@echo off
    setlocal enableextensions disabledelayedexpansion

    set "search=file2.vrt"
    set "replace=D2016001045000.level1_level2.newDATA_data2.vrt"

    set "textFile=D2016001045000.level1_level2.newDATA_main.vrt"

    for /f "delims=" %%i in ('type "%textFile%" ^& break ^> "%textFile%" ') do (
        set "line=%%i"
        setlocal enabledelayedexpansion
        set "line=!line:%search%=%replace%!"
        >>"%textFile%" echo(!line!
        endlocal
    )

But this is only good for every single file and all the time, data1 and data2 were specified individually and run individually which is not good. I want to do it with more files and replace the file1.vrt and file2.vrt simultaneously in one batch code .