hello,
i am trying desperately to measure the duration of a task called within a dos batch loop running on a windows 8.1 64 bits and an seriously asking myself if this is at all possible
Thanks in advance for your help
Tried the procedure in
http://stackoverflow.com/questions/9922 ... batch-file
the expression
set /A STARTTIME=(1%STARTTIME:~0,2%-100)*360000 + (1%STARTTIME:~3,2%-100)*6000 + (1%STARTTIME:~6,2%-100)*100 + (1%STARTTIME:~9,2%-100)
result in "Unbalanced parenthesis." whenever hour < 10
Tried the procedure in
http://www.computerhope.com/forum/index ... ic=78053.0
the expression in bold gives
"Invalid number. Numeric constants are either decimal (17), hexadecimal (0x11), or octal (021)."
whenever 8<seconds <10
echo start time=%TIME%
set HH=%TIME:~0,2%
echo Hour=%HH%
set MM=%TIME:~3,2%
echo minutes=%MM%
set /a MM=%MM% * 60
echo Total Seconds in given minutes=%MM%
set /a HH=%HH% * 3600
echo Total seconds in given Hours = %HH%
set SS=%TIME:~6,2%
echo seconds= %SS%
Set /a start=%HH% + %MM% + %SS%echo start time in seconds =%start%
