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Author Topic: Cable help  (Read 1777 times)

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nymph4

    Topic Starter


    Specialist

    Cable help
    « on: November 29, 2008, 10:22:18 PM »
    I was on the Internet looking at how Coax Cable works and I just need some help Understanding what I read.

    I know that Coax Cable has a Center Conducter that is the main wire that the signales are on.

    And around that is wrapped a none Conductive Dyelectric.

    And around that is wrapped a Braid that acts as a Shield an a Second Conducter.

    What I need help with is the outer Braid that is the Shield keeps E.M.F out of the Center Conducter I get this.

    But it also is the Second Conducter but what I want to know is this.

    Is the outer Shield conected to the outer part of the BNC Conector the part that spins around the Center Conducter???

    hiloed



      Beginner

      Thanked: 3
      Re: Cable help
      « Reply #1 on: November 29, 2008, 11:25:43 PM »

      Yes, the outer shield is connected to the outer part of of the BNC connector.

      nymph4

        Topic Starter


        Specialist

        Re: Cable help
        « Reply #2 on: November 30, 2008, 03:45:03 PM »
        So the Outer Shield is connected to the Outer part of the BNC Connecter.

        OK I get it so far.

        If you hold a BNC Connecter in your hand without it being attatched to the Cable you will see the Center Pin and the Outer part that spins.
        Are the Insolated from one onother on just the Connecter??

        nymph4

          Topic Starter


          Specialist

          Re: Cable help
          « Reply #3 on: December 01, 2008, 09:50:08 PM »
          anyone

          Woodman



            Beginner
            Re: Cable help
            « Reply #4 on: December 01, 2008, 11:42:41 PM »
            Quote
            Are the Insolated from one onother on just the Connecter??

            Yes, there is no connection between the center pin and the body of the connector.