The Intel CPU talks to the motherboard at x4 (I don't remember why, maybe someone can help us both out , so the fsb in the bios will be 250 (250x4=1000)
I think what you are referring to is
quad pumping the cpu
http://en.wikipedia.org/wiki/Pumping_%28computer_systems%29I should have been a little more specific too... I believe cpu/ram ratio refers to the memory bus speed and the
Internal cpu fsb speed...
If the external fsb is 100 MHz, then 100 x 4 =
400 MHz would be the
Internal cpu bus speed. Then
if your DDR is 200 MHz, it would equate to 400 MHz, making the ratio 1:1
So, in your example the ratio would actually be 1:2, unless I interpreted it incorrectly.
Your RAM is running at
500 MHz (250 x 2) and your Internal CPU BUS is running at
1000(250 x 4) .................thus, 1:2