What I'm trying to do is select once from the dropdown and use the selection
to update the numbersdb database via the submit button. Thanks for your help.
<?php
$dbconnect = mysqli_connect('localhost','root','');
mysqli_select_db($dbconnect, 'numbersdb') or die( "Unable to select database");
$taxrate = (isset($_POST['submit'])) ? mysqli_real_escape_string($dbconnect, $_POST['taxrate']) : '';
$id = (isset($_POST['id'])) ? mysqli_real_escape_string($dbconnect, $_POST['id']) : '';
$result = mysqli_query($dbconnect, "SELECT * FROM numbdata");
if (!empty($_POST['update_taxrate'])) {
$update = mysqli_query($dbconnect, "UPDATE numbdata SET taxrate = '$taxrate' WHERE id ='$id'");
echo "Taxrate has been set ...";
}
?>[/color]
[color=red]<!DOCTYPE html>
<html>
<head>
<title>Select taxrate</title>
<style type="text/css">
body {
background: #cff;
}
form {
text-align: center;
}
</style>
</head>
<body>
<form name="taxset" action="<?php echo $_SERVER['PHP_SELF'];?>" method="post">
<p><label>Select state/rate</label><p>
<select name="taxrate">
<option value="0.04000" selected>4% Alabama</option>
<option value="0.05600">5.6% Arkansas</option>
</select>
</p>
<!--<p><label>Update taxrate</label>
<input type="text" name="update_taxrate">-->
<p><input type="submit" name="submit" value="update"></p>
</form>
</body>
</html>
[/color]
