MS-DOS 8.0: Determine String Length?

[Ana21]

Using MS-DOS 8.0, what is the best way to determine the length of a string?

I looked through Computer Hope (http://www.computerhope.com/msdos.htm), but no commands jumped out at me...

Is there a built in command or must a function be built to address this?

Thanks a ton.

[Sidewinder]

This might help:

Code: [Select]

@echo off
setlocal
set /p var=Enter String Value:

:length
  if defined var (set var=%var:~1%& set /a length+=1 & goto length)
  echo String length is: %length% characters

Quirk Alert: %& must be concatenated in "if defined" line

MS-DOS 8? Wow! 

[patio]

Never heard of it...

[clarkegriffinx]

Using MS-DOS 8.0, what is the best way to determine the length of a string?

I looked through Computer Hope (http://www.computerhope.com/msdos.htm), but no commands jumped out at me...

Is there a built in command or must a function be built to address this?
McDVOICE MyBKExperience Liteblue

Thanks a ton

I got and example and this is it cleaned up a litte

Code: [Select]

@echo off
setlocal
set #=%1
set length=0
:loop
if defined # (set #=%#:~1%&set /A length += 1&goto loop)
echo %1 is %length% characters long!
endlocal
Here's another option. Pass the string as a paramter like this:

Code: [Select]

   LEN "this is a long string"
Here's the code:

Code: [Select]

   @echo off

   echo.%~1>len
   for %%a in (len) do set /a len=%%~za -2

   echo %len%Copy and paste the code into Notepad and save it as LEN.BAT.

NOTE: The fullstop following the ECHO statement is vital should a NUL string be entered. The -2 is required because ECHO automatically adds a CR & LF at the end of each line.