W.2K batch scripting help please.

[AlfredO]

I want to execute multiple programs in sequence.  The programs are stored in a directory named D:\Progfils.  I also want to ensure that a second and subsequent program is not started before the previous one has ended.  Can this be done?

My code so far:

Code: [Select]

@echo off
cls

: Set variable for Progfils directory
Set progfils=d:\Progfils\

: Create program file names list in alpha sequence..
Dir /on/b %progfils% > d:\temp\filename.txt

: Start program sequence..
FOR /F %%a in (d:\temp\filename.txt) do start %progfils%\a%%

At this point I need some coding to ensure that the second and subsequent program does not start before the previous one has completed.  Please indicate what command will achieve this.

Thanks.

[macdad-]

in a sequence like such in such file 1st and so in so file 2nd
or just all of the programs togther?

[AlfredO]

Sorry, I really don't understand your question.

The programs are to be run in alpha sequence from A to Z but program B must not be started before program A has finished, program C must not be started before program B has finished etc...  Only one program is to run at any time.
Thanks

[GuruGary]

Try adding the /WAIT to your START command.  Like this:

Code: [Select]

FOR /F %%a in (d:\temp\filename.txt) do start /WAIT %progfils%\a%%

[AlfredO]

Thank you, that looks like what I need.

Edit: Yes, worked like the proverbial charm, thanks again.

Alf.