How to split any line(path) throught command line (for batch file)?

[roohi]

I want to split a line (its actually a path), with the help of specific string of that line.

For example I get Path of current work dir by the command cd let it return following path :
c:/dir/xyz/abc/test1

now i only want c:/dir from this path how can i get this path ?
here one more thing is there which i want to asked in above path c:/dir may change for each user , Test 1 change for diff test but /xyz/abc are constant or fixed for each time .

so any one tell me how i get that dir path ?

i want the solution for batch files of MSDOS.

[Sidewinder]

This should work:

Code: [Select]

for /f "tokens=1-2 delims=/ " %%i in ('cd') do (
echo %%i/%%j
)


i want the solution for batch files of MSDOS.

Are you really running MS-DOS or the shell program running under Windows?
 

[roohi]

it does not works

it shows full path like

c:\dir\xyz\test1/

and i want only c:\dir

[roohi]

now i get that thanks alot

now if i want to break from abc then how can i get first part only .

means like c:\dir\xyz\abc\test1

now if delims=abc then how can i get first part because i m not sure that each user have 2 or 3 token or one token before that .

by the way thanks for help

[Sidewinder]

You need to be consistent:

c:/dir/xyz/abc/test1

c:\dir\xyz\test1/

OR write more generic code:

Code: [Select]

for /f "tokens=1-2 delims=\/" %%i in ('cd') do (
echo %%i/%%j
)


[roohi]

thanks alot for help 

now my problem is sloved .

[roohi]

Hi Sidewinder

I want to ask one more thing in delims can i specify only one character ?

because i tried to give test so it matches t , e , s  speratally and deletes all .

I mean if I want to match whole word test then?

[Dias de verano]

This should work:

Code: [Select]

for /f "tokens=1-2 delims=/ " %%i in ('cd') do (
echo %%i/%%j
)


i want the solution for batch files of MSDOS.

Are you really running MS-DOS or the shell program running under Windows?
 

Let's have a little OS quiz -

1. Which OS family uses a forward slash ("/") as a path delimiter? Is it:

(a) Unix/Linux
(b) Microsoft MS-DOS/Windows?

2. Which OS family uses a backward slash ("\") as a path delimiter? Is it:

(a) Unix/Linux
(b) Microsoft MS-DOS/Windows?

[Sidewinder]

Hi Sidewinder

I want to ask one more thing in delims can i specify only one character ?

because i tried to give test so it matches t , e , s  speratally and deletes all .

I mean if I want to match whole word test then?

You can have a multiple delims. Each character acts as a delimiter.

In your case I would recommend dumping the %CD% value in a text file and search for the value test:

Sample code:

Code: [Select]

@echo off
echo %cd% > test.txt
find /i "test" test.txt > nul
if errorlevel 1 echo not found && goto :eof
if errorlevel 0 echo found && goto :eof

 

[roohi]

I used the following code :

for /f "tokens=1-10 delims=\" %%a in ('cd') do (
   if %%b==test echo %%a
   if %%c==test echo %%a/%%b
   if %%d==test echo %%a/%%b/%%c
   if %%e==test echo %%a/%%b/%%c/%%d
   if %%f==test echo %%a/%%b/%%c/%%d/%%e
   )

i know its not a good option but for a time begin i used that .

[roohi]

hello

finally i used following code can some one plz tell me how i can append the value of g in p variable.

for /f "tokens=1-10 delims=\" %%1 in ('cd') do (
      set p=%%1
   for %%G in (%%1, %%2, %%3, %%4, %%5, %%6, %%7, %%8, %%9, %%10) do (
      if %%G==test echo %p%
      set p=.................
      echo %%G     
   )
   
)

[Sidewinder]

I'm still not certain what you are trying to do. At first I thought you  wanted to see if test was in the current directory. Now, based on your code, I think you want to build a path using the parents of the test directory.

Try not to use the numeric variables within a for loop. While perfectly legal, it only adds confusion with the command line arguments.

Going with the theory that you want to build a path with the parents of test, this may help you out:

Code: [Select]

@echo off
setlocal enabledelayedexpansion
for /f "tokens=* delims=\" %%a in ('cd') do (
set parse=%%a
set new=!parse:\= !
)

for %%G in (%new%) do (
if .%%G==. goto getout
  if %%G==test goto getout
  call set p=%%p%%\%%G
)
:getout
set p=%p:~1%
echo %p% 

We're here 24/7, so if I guessed wrong, be sure to let us know.

[roohi]

Thanks Alot

its a currect solution and i got path currectally but i got it twice, thats not a issue .

As i m bigginer in batch file programming one thing what i does not understude in this code is

if .%%G==. goto getout

can u plz tell me what this line is done .

Thank u again

[Sidewinder]

Code: [Select]

if .%%G==. goto getout

The line checks to see if %%G is blank (meaning end of path) and exits the for loop. Writing the code without some character (in this case a dot) will produce an error.  The interpreter uses spaces as a delimiter.

Any character can be used in place of the dot.  Personally I use the dot out of tradition and because it's lowercase on the keyboard.

 

[roohi]

Thanks for explaning