Did anyone else think it might not fit either? Anyways, when you take the speaker out it usually says the ohms. It is ok to replace the speaker with something of a higher impedance, but the wattage will be reduced, thus not as loud.
I may be wrong but I disagree. What happens with any circuit when introduce to a '0' ohm load? (just for example)
The wattage increases to whatever is the maximum wattage available in the supply circuit. Unless the circuit is fused lower than this load, the circuit shorts to ground and is no longer healthy.
I'll post a chart for ohms law pertaining to DC (direct current) voltage which is used in most speaker systems.
AMPS= WATTS÷VOLTS I = P ÷ E A = W ÷ V
WATTS= VOLTS x AMPS P = E x I W = V x A
VOLTS= WATTS ÷ AMPS E = P ÷ I V = W ÷ A
HORSEPOWER= (V x A x EFF)÷746
EFFICIENCY= (746 x HP)÷(V x A)
Here's the key chart for those symbols
E =VOLTS ~or~ (V = VOLTS)
P =WATTS ~or~ (W = WATTS)
R = OHMS ~or~ (R = RESISTANCE)
I =AMPERES ~or~ (A = AMPERES)
HP = HORSEPOWER
PF = POWER FACTOR
kW = KILOWATTS
kWh = KILOWATT HOUR
VA = VOLT-AMPERES
kVA = KILOVOLT-AMPERES
C = CAPACITANCE
EFF = EFFICIENCY (expressed as a decimal)
Yes i've run higher impedimence speakers on several sound systems that were not stable operating as such, but the sound is muddy and the system is overworked. And some of them didn't survive. I'd try it on my 9 year old EMachines but not on my $1500 quad core build. JMO